If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12p^2-30p=0
a = 12; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·12·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*12}=\frac{0}{24} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*12}=\frac{60}{24} =2+1/2 $
| (8x-9)+53=180 | | 0.66=1-x | | 7-1/3x=3/2-1/2x | | 5(6x+4)-8=5x+2 | | y/8y=8 | | 5(6x+4)-8=5x+13 | | 8-d-(-12)=14+3d | | 9z-3=30 | | 6/11-7b/11=24/11 | | 5(6x+4)-8=5x+7 | | 3r-7=27 | | 1-1/3x^-2/3=0 | | 97-x=64 | | -2=c−-1-3 | | 25+3x-10+x+15=18 | | 5(6x+4)-8=3x+6 | | 0.5(5−7x)=8−(4x+6) | | -63=4x-18-15 | | 5(6x+4)-8=6x+2 | | (8-n)^2=2(24-n^2) | | 15=w/3-14 | | √x+3−6x=3 | | 12w=-21 | | 5^x+3-4=19 | | 3x=15+60 | | 3x+2=3x−1 | | 3w+6=3w+ | | 185=43-u | | -10=7x=32 | | -20s-1=-4s-17 | | -2(−6m−3)=6(5m−1) | | a+3-4=-12 |